标题翻译
Retrieve Alternative entityManager on unit test though CDI
问题
我正在使用Junit 5，在webapp EE8环境下运行的Java批处理。
在Web应用程序中，实际上我有一个被用作生产者的资源类：
@ApplicationScoped
public class Resources {
@Produces
public Logger produceLog(InjectionPoint injectionPoint) {
return LoggerFactory.getLogger(injectionPoint.getMember().getDeclaringClass().getName());
}
@Produces
@PersistenceContext(unitName = "primary")
private EntityManager entityManager;
}
现在我想编写一些SE（标准版）测试，并且需要获取一个备用的实体管理器，类似于：
public class MockResources {
@Alternative
@JobScoped
@Produces
public EntityManager getEntityManager() {
return Persistence.createEntityManagerFactory("primary").createEntityManager();
}
}
问题是我不知道如何检索这个备用的实体管理器，因为 beans.xml 需要一个类（我尝试过使用Hibernate SessionImpl 但它不起作用），也不适合使用 @Stereotype。
<beans xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/beans_1_1.xsd"
bean-discovery-mode="all">
<alternatives>
<class>org.hibernate.internal.SessionImpl</class>
</alternatives>
</beans>
有任何帮助吗？
英文翻译
I'm using Junit 5, Java bath that run under a webapp EE8 environment.
On the web app, I actually have a resources class that is employed as a producer:
@ApplicationScoped
public class Resources {
@Produces
public Logger produceLog(InjectionPoint injectionPoint) {
return LoggerFactory.getLogger(injectionPoint.getMember().getDeclaringClass().getName());
}
@Produces
@PersistenceContext(unitName = "primary")
private EntityManager entityManager;
}
Now I want to write some SE test, and I need to retrieve an alternative entity manager, something like:
public class MockResources {
@Alternative
@JobScoped
@Produces
public EntityManager getEntityManager() {
return Persistence.createEntityManagerFactory("primary").createEntityManager();
}
}
The issue is that I don't know how to retrieve this alternative entity , as beans.xml want a class (I tried with Hibernate SessionImpl but it doesn't work), neither @Stereotype looks good for my case.
<beans xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/beans_1_1.xsd"
bean-discovery-mode="all">
<alternatives>
<class>org.hibernate.internal.SessionImpl</class>
</alternatives>
</beans>
Any help ?
答案1
得分: 0
你应该创建一个完整的@Alternative资源生产者bean，就像这样：
@Alternative
@ApplicationScoped
public class TestResources {
@Produces
public Logger produceLog(InjectionPoint injectionPoint) {
return LoggerFactory.getLogger(injectionPoint.getMember().getDeclaringClass().getName());
}
@Produces
private EntityManager getEntityManager() {
// 在此处创建新的EntityManager
return Persistence.createEntityManagerFactory("testunitname").createEntityManager();
}
}
然后按照你的问题中描述的方式，在测试的beans.xml文件中定义你的测试备选类。
英文翻译
You should create an entire @Alternative Resources producer bean, as in
@Alternative
@ApplicationScoped
public class TestResources {
@Produces
public Logger produceLog(InjectionPoint injectionPoint) {
return LoggerFactory.getLogger(injectionPoint.getMember().getDeclaringClass().getName());
}
@Produces
private EntityManager getEntityManager() {
// create your new entitymanager here
return Persistence.createEntityManagerFactory("testunitname").createEntityManager();
}
}
Then define your test alternative class on test beans.xml as described on your question.
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