标题翻译
Efficient way to save last X amount of integers
问题
我获取各种数据，每秒更新一次。我需要编写一个函数，以给我某个属性最近 30 个值（最近 30 秒）的值。什么方法在占用内存最少的情况下保存最近 30 个值？30 秒之前的所有数据都可以丢弃。我需要每秒执行此操作 96,000 次。
英文翻译
I get all kinds of data, which gets updated every second. I need to write a function that gives me the last 30 values (of the last 30 seconds) of a certain attribute. What would be the most memory-efficient way to save the last 30 values of something? Everything older than 30 seconds can be discarded. I have to do this action 96k times/second.
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