英文:
JpaSystemException - cannot set field value [auditEntity] extend extended entity
问题
我有一个自定义的库 - 用于实体的AuditBase。有一个带有@MappedSuperclass，@EntityListener和@RevisionEntity的类。
在当前项目中，有一个名为'area'的实体。这个实体是@MappedSuperclass。
另外还有两个实体扩展自AreaEntity：
最后一个实体与PlaceEntity有关联：
我有一个简单的JpaRepository查询：
在使用它后，我得到了如下异常：
我不知道如何解决这个问题。有人可以帮忙吗？
英文:
i have custom lib - auditBase for entities. there is class with @MappedSuperclass, @EntityListener and @RevisionEntity.
@RevisionEntity
@MappedSuperclass
@EntityListeners({AuditListener.class})
public class AuditBase {
@Column(
name = "client_app_id"
)
private String audit_clientAppId;
@Column(
name = "company_id"
)
private Long audit_companyId;
@Column(
name = "insert_date"
)...
in current project there is Entity for example named 'area'. this entity is @MappedSuperclass
@Entity
@Table(name = "area")
@Inheritance(strategy = InheritanceType.JOINED)
@Getter
@Setter
public class AreaEntity extends AuditBase {
@Id
@SequenceGenerator(name = "area", sequenceName = "area", allocationSize = 1)
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "area")
@Column(name = "area")
private Long id;
@Column(name = "json_in_out_afp", columnDefinition = "TEXT")
private String jsonInOutAfp;
@Column(name = "afp_external_id", nullable = false, unique = true)
private Integer afpExternalId;
@Column(name = "area_status", length = 8, nullable = false)
private String areaStatus;...
Another two entities extends AreaEntity:
@Entity
@Table(name = "place")
@Getter
@Setter
public class PlaceEntity extends AreaEntity implements Serializable {
@Column(name = "kind_of_place", nullable = false, length = 8)
private String kindOfPlace;
@Column(name = "measurement", nullable = false)
private boolean measurement;
@Column(name = "place_shape_type", nullable = false, length = 8)
private String placeShapeType;
@ManyToOne(targetEntity = PlaceSubAreaEntity.class)
@JoinColumn(name = "fk_place_sub_area", insertable = true, updatable = true)
private PlaceSubAreaEntity placeSubAreaEntity;...
Last entity with relation to PlaceEntity:
@Entity
@Table(name = "parking_place_sub_area")
@Getter
@Setter
public class PlaceSubAreaEntity extends AreaEntity implements Serializable {
@OneToMany
private Set<PlaceEntity> placeEntities = new HashSet<>();...
I have one simple query JpaRepository
@Repository
public interface PlaceRepository extends JpaRepository<PlaceEntity, Long> {
@Query("select place from PlaceEntity place where place.afpExternalId = :afpExternalId")
PlaceEntity findByAfpExternalId(@Param("afpExternalId") Integer afpExternalId);
after use it i have exception like this:
org.springframework.orm.jpa.JpaSystemException: Could not set field value [AuditBase(audit_clientAppId=null, audit_companyId=null, audit_insertDate=null, audit_insertedBy=null, audit_updateDate=null, audit_updatedBy=null, audit_updateClientAppId=null, audit_operatorId=null, audit_app=null, audit_appNo=null, audit_appResNo=null, audit_appVer=null, audit_appTraceId=null, audit_appSpanId=null)] value by reflection : [class PlaceEntity.placeSubAreaEntity] setter of PlaceEntity.placeSubAreaEntity; nested exception is org.hibernate.PropertyAccessException: Could not set field value [AuditBase(audit_clientAppId=null, audit_companyId=null, audit_insertDate=null, audit_insertedBy=null, audit_updateDate=null, audit_updatedBy=null, audit_updateClientAppId=null, audit_operatorId=null, audit_app=null, audit_appNo=null, audit_appResNo=null, audit_appVer=null, audit_appTraceId=null, audit_appSpanId=null)] value by reflection : [class PlaceEntity.placeSubAreaEntity] setter of PlaceEntity.placeSubAreaEntity
I have no idea how resolve this problem. Anyone can help?
答案1
得分: 0
在这种情况下，我使用了鉴别器列。它解决了我的问题。
英文:
In this case, i used discriminator column. it solved my problem.
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