英文:
Jackson serialization ignores '@JsonTypeInfo' and '@JsonIgnore' for Iterator classes?
问题
我最近从Jackson 2.9.10升级到2.10.0，并注意到迭代器类的序列化方式发生了变化。
在下面的测试中，使用2.9.10版本（处理JsonTypeInfo和JsonIgnore）的输出为：
{"@class":"IteratorTest"}
但是在2.10.0版本中，JsontTypeInfo和JsonIgnore未被处理，输出为：
["IteratorTest",["one","two"]]
新的序列化行为是否正确？是否有方法来获得旧的行为？
// 测试类import java.util.Iterator;import java.util.ArrayList;import java.util.List;import com.fasterxml.jackson.databind.ObjectMapper;import java.io.IOException;import com.fasterxml.jackson.annotation.JsonIgnore;import com.fasterxml.jackson.annotation.JsonTypeInfo;@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "class", visible=true)public class IteratorTest<T> implements Iterator<T> {@JsonIgnoreprivate Iterator<T> iterData;private static final ObjectMapper MAPPER = new ObjectMapper();IteratorTest(Iterator<T> iterData) { this.iterData = iterData; }@Overridepublic boolean hasNext() {return iterData.hasNext();}@Overridepublic T next() {return iterData.next();}public static void main(String[] args) throws IOException {List<String> strings = new ArrayList<>();strings.add("one");strings.add("two");IteratorTest<String> it = new IteratorTest<>(strings.iterator());System.out.println("-- serializing --");String s = MAPPER.writeValueAsString(it);System.out.println(s);}}// 测试类结尾
英文:
I've recently upgraded from Jackson 2.9.10 to 2.10.0 and notice a change in how Iterator classes are serialized.
Given the test below, the output with 2.9.10 (with handling of JsonTypeInfo and JsonIgnore) is
{"@class":"IteratorTest"}
but with 2.10.0, JsontTypeInfo and JsonIgnore are not processed, and the output is
["IteratorTest",["one","two"]]
Is the new serialization behavior correct? Is there a workaround to get the old behavior?
// Test classimport java.util.Iterator;import java.util.ArrayList;import java.util.List;import com.fasterxml.jackson.databind.ObjectMapper;import java.io.IOException;import com.fasterxml.jackson.annotation.JsonIgnore;import com.fasterxml.jackson.annotation.JsonTypeInfo;@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "@class", visible=true)public class IteratorTest<T> implements Iterator<T> {@JsonIgnoreprivate Iterator<T> iterData;private static final ObjectMapper MAPPER = new ObjectMapper();IteratorTest(Iterator<T> iterData) { this.iterData = iterData; }@Overridepublic boolean hasNext() {return iterData.hasNext();}@Overridepublic T next() {return iterData.next();}public static void main(String[] args) throws IOException {List<String> strings = new ArrayList<>();strings.add("one");strings.add("two");IteratorTest<String> it = new IteratorTest<>(strings.iterator());System.out.println("-- serializing --");String s = MAPPER.writeValueAsString(it);System.out.println(s);}}// end of Test class
答案1
得分: 0
是的，在版本2.9.10中，您会得到一个BeanSerializer，而在版本2.10.0中，您会得到一个IteratorSerializer。
在版本2.10.0中，当您的类没有任何属性时（BeanSerializerFactory.findSerializerByAddonType），您会得到IteratorSerializer。而在版本2.9.10中，您可以从builder.createDummy()获得一个BeanSerializer。
修复方法：
- 使用自定义序列化程序
- 或许更改您的OM的Iterator类处理方式
- 使用现有的属性，以便创建
BeanSerializer（这将给您不同的JSON）：
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.EXISTING_PROPERTY, property = "myClass")class IteratorTest<T> implements Iterator<T> {private String myClass = IteratorTest.class.getSimpleName();...}
英文:
Yes, debugging it, with version 2.9.10 you get a BeanSerializer, with version 2.10.0 you get a IteratorSerializer.
In version 2.10.0, you get the IteratorSerializer when your class does not have any properties (BeanSerializerFactory.findSerializerByAddonType). In version 2.9.10, you get a BeanSerializer from builder.createDummy().
Fix:
-
Use a custom serializer
-
maybe change the handling of Iterator-Classes for your OM
-
Use an existing property, s.t. a
BeanSerializeris created (this would give you a different json):@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.EXISTING_PROPERTY, property = "myClass")class IteratorTest<T> implements Iterator<T> {private String myClass = IteratorTest.class.getSimpleName();...}
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