标题翻译
Cant display date as yyyy-MM-dd'T'HH:mm:ss:SSS Java
问题
以下是翻译好的部分：
我在尝试转换以下字符串时遇到了以下错误。我希望日期的格式为 yyyy-MM-dd'T'HH:mm:ss:SSS，但实际上日期似乎显示为 Sun Mar 01 23:00:01 GMT 2020
String FULL_ISO_DATE_FORMAT = "yyyy-MM-dd'T'HH:mm:ss.SSS";
SimpleDateFormat formatter = new SimpleDateFormat(FULL_ISO_DATE_FORMAT);
Date from = formatter.parse("2020-03-01T23:00:01.000");
错误信息
feign.FeignException: 状态码 400，在 Controller#searchController(Date,Date,Integer,String) 读取内容时出错：
{"status":"fail","data":{"errors":[{"type":"IllegalArgumentException","description":"无效值 Sun Mar 01 23:00:01 GMT 2020 用于过滤器 from。字段必须符合格式：yyyy-MM-dd'T'HH:mm:ss.SSS"}]}}
任何帮助将不胜感激。我需要使用 Date 对象，因为我正在查询的构造函数使用 Date 对象。理想情况下，我想使用 LocalDateTime，但我不能。
英文翻译
Im getting the following error when I try to convert the following string. Id like the Date to be in the format yyyy-MM-dd'T'HH:mm:ss:SSS but instead the Date seems to be coming out as Sun Mar 01 23:00:01 GMT 2020
String FULL_ISO_DATE_FORMAT = "yyyy-MM-dd'T'HH:mm:ss.SSS";
SimpleDateFormat formatter = new SimpleDateFormat(FULL_ISO_DATE_FORMAT);
Date from = formatter.parse("2020-03-01T23:00:01.000");
Error
feign.FeignException: status 400 reading Controller#searchController(Date,Date,Integer,String); content:
{"status":"fail","data":{"errors":[{"type":"IllegalArgumentException","description":"Invalid value Sun Mar 01 23:00:01 GMT 2020 for filter from. Field needs to be in format: yyyy-MM-dd'T'HH:mm:ss.SSS"}]}]}
Any help would be appreciated. I need to use the Date object as the constructor Im querying is using the Date object. Ideally I'd like to use LocalDateTime but I cant.
答案1
得分: 1
使用来自Java 8 日期时间API 的LocalDateTime，停止使用旧的Date类
String FULL_ISO_DATE_FORMAT = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.now();
dateTime.format(FULL_ISO_DATE_FORMAT);
英文翻译
Use the LocalDateTime from java-8 date-time API and stop using legacy Date classes
String FULL_ISO_DATE_FORMAT = DateTimeFormatter. ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime dateTime = LocalDateTime.now();
dateTime.format(FULL_ISO_DATE_FORMAT);
答案2
得分: 1
请不要使用旧的类Date和SimpleDateFormat。使用更为强大和设计更合理的新的java.time API。
您可以按以下方式执行相同的操作：
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime date = LocalDateTime.parse("2020-03-01T23:00:01.000", formatter);
请注意，您可以按以下方式将其转换为Date以实现兼容性：
Date legacyDate = Date.from(date.atZone(ZoneId.systemDefault()).toInstant());
英文翻译
Please don't use the old classes Date and SimpleDateFormat. Use the new java.time api that is much more robust and better designed.
You can do the same thing as follows:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS");
LocalDateTime date = LocalDateTime.parse("2020-03-01T23:00:01.000", formatter);
Keep in mind that you can convert it to Date for compatibility like so:
Date legacyDate = Date.from(date.atZone(ZoneId.systemDefault()).toInstant());
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