英文:
How to keep scnr.hasNext() true
问题
我正在调试代码的一部分，我意识到它不按照我的预期工作。我想输入一些数字，让 int var 逐个存储它们，如果有更多的数字输入，保持 scnr.hasNext() 为 true，以便我的 while 循环继续运行，并且我可以对每个数字执行操作。
public static Number evaluateExpression(String expr) {
Scanner scnr = new Scanner(expr);
int var = 0;
while (scnr.hasNext()) {
System.out.println(scnr.hasNext());
var = scnr.nextInt();
System.out.println(scnr.hasNext());
}
}
目前，如果我输入 5、4，输出为 true false false，所以 var = scnr.nextInt(); 使得 (scnr.hasNext()); 变为 false。我该如何修复这个问题？我还需要一种方法来存储下一个 scnr 值，如果它是一个字符串，那么
String input = "";
input = scnr.next();
会在有更多输入时保持 scnr.hasNext() 为 true。
英文:
I am debugging a part of my code that I have realized isn't working how I want it. I want to enter a couple numbers and have int var store them one by one, and keep scnr.hasNext() true if there were more numbers inputted, so that my while loop continues and I can run operations on every number.
public static Number evaluateExpression(String expr) {
Scanner scnr = new Scanner(expr);
int var = 0;
while (scnr.hasNext()) {
System.out.println(scnr.hasNext());
var = scnr.nextInt();
System.out.println(scnr.hasNext());
}
Currently if I give it input of 5, 4, the output is true false false, so var = scnr.nextInt(); is making (scnr.hasNext()); false. How do I fix that? I also need a way to store the next scnr value if it is a string too, so
String input = "";
input = scnr.next();
would keep scnr.hasNext() true if there is more input given.
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