英文:
How to validate the user input is in a certain range?
问题
我编写了一个程序，询问用户输入介于1到6之间的数字字符串，然后返回获得该字符串所需的投掷次数。我想要验证输入，以防止用户输入大于6或小于1的数字，但我似乎无法弄清楚如何实现。
int SIDES = 6;
String userString = "null";
String answer = "null";
int length = 0;
do {
do {
System.out.print("请输入一个包含6个数字的字符串，用于投掷：");
userString = keyboard.next();
while (length != SIDES) {
System.out.println("请输入一个有效的数字字符串：");
userString = keyboard.next();
}
length = userString.length();
} while (length != SIDES); // 我想在这行添加验证
dieRoll(userString);
}
英文:
I wrote a program that asks the person for strings of numbers between 1-6 and returns the number of rolls it took to get the string. I want to validate the input so that the person doesn't enter a number bigger than 6 or smaller than 1 and I can't seem to figure out how to do that.
int SIDES = 6;
String userString = "null";
String answer = "null";
int length = 0;
do {
do {
System.out.print("please enter a string of 6 numbers you want to be rolled");
userString = keyboard.next();
while (length != SIDES) {
System.out.println("please enter a valid string number");
userString = keyboard.next();
}
length = userString.length();
} while ( length != SIDES); // I want to add the validation to this line
dieRoll(userString);
答案1
得分: 0
while (length != SIDES) {
userString = keyboard.next();
try {
int userStringNumber = Integer.parseInt(userString);
if (userStringNumber < 1 || userStringNumber > 6)
throw new IllegalArgumentException();
} catch (NumberFormatException e) {
System.out.println("Please provide a number");
}
catch (IllegalArgumentException ex){
System.out.println("Number should be between 1 and 6");
}
}
英文:
while (length != SIDES) {
userString = keyboard.next();
try {
int userStringNumber = Integer.parseInt(userString);
if(userStringNumber<1||userStringNumber>6)
throw new IllegalArgumentException();
} catch (NumberFormatException e) {
System.out.println("Please provide a number");
}
catch (IllegalArgumentException ex){
System.out.println("Number should be between 1 and 6");
}
}
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