英文:
finding object reference in array by index
问题
正如标题所述，我正在尝试通过传入显式索引值并在数组中搜索以确定索引/对象是否存在，判断是否存在，然后如果存在，则返回该值/对象引用，否则返回 null。
for (int i = 0; i < nextPos - 1; i++) {
if (i == inIndex) {
i = inIndex;
return results[i];
}
}
// 如果没有找到，应该执行以下操作
return null;
nextPos 是表示数组中有多少个“槽位”填充的伴随变量。
inIndex 是显式索引。
在我的代码中，我假设它会遍历整个循环，如果当前位置 i 等于索引，则应该将 i 设置为 inIndex，并返回相应的值，但我一直得到 null 结果。
我已经确认数组已经填充了 50 个值。
我不知道我在这里做错了什么。
数组 results 是持有数组的对象引用。
更新：nextPos 已经设置为等于数组 results 中的填充位置
{
if (this.nextPos < this.results.length){
this.nextPos++;
}
return nextPos;
}
inIndex 是我正在搜索的索引，
如上所述，我正在尝试在 results 数组中找到对象的索引，使用我传入的 InIndex 值，然后一旦找到，返回该索引处包含的值。如果该索引不存在，则返回 null。
英文:
As the title says i'm trying to determine if a index/object exists by passing in a explicit index value and then searching for it in the array, determining if it exists, then if it exist,then returns the value/object reference there else returns null.
for (int i = 0; i < nextPos -1; i++) {
if (i == inIndex) {
i = inIndex;
return results[i];
}
// here is what its supposed to do if it doesnt find one
return null;
nextPos is the companion variable for how many "slots" in a array they are filled.
inIndex is the explicit
In my code here I'm assuming it loops throught the entire loop and if i the current position is equal to the index it should set i to equal inIndex; then return whatever there but i just keep getting a null result
i have already confirmed that the array is full with 50 values
i dont know what i am doing wrong here
array results is a object reference holding array
update: nextPos is already set to equal the filled postions in array results
{
if (this.nextPos < this.results.length){
this.nextPos++;
}
return nextPos;
inIndex is the index im searching for,
as said above im trying to find the index of a object in results array, using the InIndex i pass in whatever the value is, and then once found return the value contained at that index, if that index does not exist, return null
答案1
得分: 0
根据我理解，您想通过索引在数组中查找对象。请尝试以下代码：
public String findObjectByIndex(int indexToFind) {
String[] names = {"name1", "name2", "name3", "name4", "name5", "name6", "name7"};
try {
return names[indexToFind];
} catch (ArrayIndexOutOfBoundsException arrayindexException) {
System.out.println("数组中未找到给定的索引");
}
return null;
}
英文:
As per my understanding you are trying to find Object in array by index. Try with below code
public String findObjectByIndex(int indexToFind) {
String[] names= {"name1","name2","name3","name4","name5","name6","name7"};
try {
return names[indexToFind];
}catch(ArrayIndexOutOfBoundsException arrayindexException) {
System.out.println("The given index not found in the array");
}
return null;
}
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