英文:
How to make a simple GUI open another GUI and detect when it closes
问题
public class MainGUI extends JFrame {
// ... (other code remains the same)
public MainGUI(String name) {
// ... (other code remains the same)
insert.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent event) {
// opens the input GUI window
InputGUI input = new InputGUI("Input GUI");
input.addWindowListener(new WindowAdapter() {
@Override
public void windowClosed(WindowEvent e) {
setVisible(true); // Reappear the main GUI when input GUI is closed
}
});
}
});
// ... (other code remains the same)
}
// ... (other code remains the same)
}
public class InputGUI extends JFrame {
// ... (other code remains the same)
public InputGUI(String name) {
// ... (other code remains the same)
ret.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent event) {
String cmd = event.getActionCommand();
if (cmd.contentEquals("Return to Main Window")) {
dispose(); // Closes the input GUI
}
}
});
// ... (other code remains the same)
}
// ... (other code remains the same)
}
请注意，以上提供的只是代码的翻译部分。如果您有关于代码的进一步问题或者需要解释，请随时提问。
英文:
So im trying to create a simple GUI in which it has the option to enter multiple inputs. I want there to exist a main menu GUI and a input GUI. The question is, how can I make the main GUI disappear when "input" is selected, and reappear when "return to main menu" is selected?
<p> Here is my main menu(unfinished)
public class MainGUI extends JFrame{
private JButton insert, find, browse, create;
public MainGUI(String name) {
super(name);
setLayout(null);
insert = new JButton("Insert");
find = new JButton("Find");
browse = new JButton("Browse");
create = new JButton("Create Tree From File");
insert.setBounds(25, 200, 100, 30);
find.setBounds(125, 200, 100, 30);
browse.setBounds(225, 200, 100, 30);
create.setBounds(325, 200, 200, 30);
setVisible(true);
setSize(600, 300);
setResizable(false);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
add(insert);
add(find);
add(browse);
add(create);
insert.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent event) {
//opens the input GUI window
InputGUI input = new InputGUI("Input GUI");
/*I was thinking of adding an if statement here, but it turns
*out that the if statement executes immediately after the inputGUI is made...
*/
}
});
//more action listener stuff here
}
public static void main (String [] args) {
MainGUI gui = new MainGUI("Main Window");
}
}
...and here is the input GUI class (unfinished)
private JButton insert, ret;
public InputGUI(String name) {
super(name);
setLayout(null);
insert = new JButton("Insert");
ret = new JButton("Return to Main Window");
insert.setBounds(50, 100, 100, 30);
ret.setBounds(150, 100, 200, 30);
setVisible(true);
setSize(400, 200);
setResizable(false);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
add(insert);
add(ret);
ret.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent event) {
String cmd = event.getActionCommand();
if(cmd.contentEquals("Return to Main Window")) {
dispose();
//how can i detect from the main menu gui that this was disposed?
}
}
});
//more action listener stuff
}
public static void main (String [] args) {
InputGUI gui = new InputGUI("Input Window");
}
}
Any help is appreciated!
答案1
得分: 0
使一个窗口在不丢失其内容/数据的情况下 "消失"，只需在 MainGUI 对象上调用 setVisible(false)。
如果您想要它 "重新出现"，再次运行 gui.setVisible(true)。
英文:
To make a window "disappear" without losing its content/data simply invoke setVisible(false) on the MainGUI object.
If you would like it to "reappear" run gui.setVisible(true) again.
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