英文:
How to get the path of a Bitmap to use in Uri
问题
我正在尝试分享一张图片。为此，我需要位图的路径以便将其作为 Uri 发送。
我目前使用的代码行已经过时，并且根据 API 结果可能为 Null。
String path = MediaStore.Images.Media.insertImage(getContentResolver(), bitmap, "Challengers", null);
获取位图路径的正确方法是什么，以便使用 Uri 将位图分享到其他应用程序？
提前感谢您的帮助。
英文:
I am trying to share an image. To do so i need the path of the bitmap to send it in Uri.
The current line i have is deprecated and depending on the API result Null.
String path = MediaStore.Images.Media.insertImage(getContentResolver(), bitmap, "Challengers", null);
What is the proper way to get the path of a Bitmap to share a Bitmap to other app using Uri?
Thanks in advance for your help.
答案1
得分: 0
终于找到了问题的原因。我已经在清单文件中添加了权限，但还需要在onCreate方法中添加几行代码：
ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE}, requestCode);
onRequestPermissionsResult(requestCode, new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE}, grantResults);
英文:
Finally found what was causing problems. I had put permissions in the Manifest but also needed to add a couple lines in onCreate
ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE},requestCode);
onRequestPermissionsResult(requestCode,new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE},grantResults);
答案2
得分: 0
这可能会有所帮助
public static Bitmap getBitmapFromURL(String imgUrl) {
try {
URL url = new URL(imgUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
return myBitmap;
} catch (IOException e) {
// 记录异常
return null;
}
}
英文:
This might help
public static Bitmap getBitmapFromURL(String imgUrl) {
try {
URL url = new URL(imgUrl);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
return myBitmap;
} catch (IOException e) {
// Log exception
return null;
}
}
答案3
得分: -1
以下是您可以尝试的代码以获取图像 URI：
public Uri getImageUri(Context inContext, Bitmap inImage) {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
return Uri.parse(path);
}
英文:
You can try below code to get Image Uri,
public Uri getImageUri(Context inContext, Bitmap inImage) {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
return Uri.parse(path);
}
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