英文:
design many-to-many relationship throwing org.springframework.beans.factory.BeanCreationException
问题
I want to design a many-to-many relationship for students to choose courses. At first, I used the many-to-many relationship directly, and then reported an error. Because I am a novice, I am not very clear about the specific rules. I suspect that there cannot be two relationships between the two entities, so I changed to the following way of writing, but it still reported the same error. I think I did follow the tutorial, but I really don't know where is wrong. So I have to ask for help.
User
@Entity
@Table(name = "user")
@JsonIgnoreProperties({"handler", "hibernateLazyInitializer"})
public class User {
// ... (other attributes and getters/setters)
@OneToMany(targetEntity = UserCourse.class, mappedBy = "student")
private List<UserCourse> ars;
// ... (getter and setter for 'ars')
}
Course
@Entity
@Table(name = "course")
@JsonIgnoreProperties({"handler", "hibernateLazyInitializer"})
public class Course {
// ... (other attributes and getters/setters)
@OneToMany(targetEntity = UserCourse.class, mappedBy = "course")
private List<UserCourse> ars;
// ... (getter and setter for 'ars')
}
UserCourse
@Entity
@Table(name = "user_course")
@JsonIgnoreProperties({"handler", "hibernateLazyInitializer"})
public class UserCourse {
// ... (other attributes and getters/setters)
@ManyToOne
@JoinColumn(name = "uid")
private User student;
// ... (getter and setter for 'student')
@ManyToOne
@JoinColumn(name = "cid")
private Course course;
// ... (getter and setter for 'course')
}
Error Message:
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(ars)]
...
Caused by: org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(ars)]
...
Thank you very much for your help.
英文:
I want to design a many-to-many relationship for students to choose courses. At first, I used the many-to-many relationship directly, and then reported an error. Because I am a novice, I am not very clear about the specific rules. I suspect that there cannot be two relationships between the two entities, so I changed to the following way of writing, but it still reported the same error. I think I did follow the tutorial, but I really dont know where is wrong. So I have to ask for help.Below is the code.
User
@Entity
@Table(name = "user")
@JsonIgnoreProperties({"handler", "hibernateLazyInitializer"})
public class User {
private int id;
private int rid;
private String name;
private String password;
private String salt;
private String email;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Basic
@Column(name = "email")
public String getEmail(){
return email;
}
public void setEmail(String email) {
this.email = email;
}
@Basic
@Column(name = "name")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Basic
@Column(name = "password")
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
@Basic
@Column(name = "salt")
public String getSalt() {
return salt;
}
public void setSalt(String salt) {
this.salt = salt;
}
@Basic
@Column(name = "rid")
public int getRid() {
return rid;
}
public void setRid(int rid) {
this.rid = rid;
}
@OneToMany(targetEntity=UserCourse.class,mappedBy = "student")
private List<UserCourse> ars;
public List<UserCourse> getArs() {
return ars;
}
public void setArs(List<UserCourse> ars) {
this.ars = ars;
}
}
Course
@Entity
@Table(name = "course")
@JsonIgnoreProperties({ "handler","hibernateLazyInitializer" })
public class Course {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private int id;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Column(name = "name")
private String name;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@ManyToOne
@JoinColumn(name="sid")
private Subject subject;
public Subject getSubject() {
return subject;
}
public void setSubject(Subject subject) {
this.subject = subject;
}
@ManyToOne
@JoinColumn(name="tid")
private User user;
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
@OneToMany(targetEntity=UserCourse.class,mappedBy = "course")
private List<UserCourse> ars;
public List<UserCourse> getArs() {
return ars;
}
public void setArs(List<UserCourse> ars) {
this.ars = ars;
}
}
UserCourse
@Entity
@Table(name = "user_course")
@JsonIgnoreProperties({ "handler","hibernateLazyInitializer" })
public class UserCourse {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private int id;
public void setId(int id) {
this.id = id;
}
public int getId() {
return id;
}
@ManyToOne
@JoinColumn(name = "uid")
private User student;
public User getStudent() {
return student;
}
public void setStudent(User student) {
this.student = student;
}
@ManyToOne
@JoinColumn(name = "cid")
private Course course;
public Course getCourse() {
return course;
}
public void setCourse(Course course) {
this.course = course;
}
}
and the error
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(ars)]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1796) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:595) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:517) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractBeanFactory.lambda$doGetBean$0(AbstractBeanFactory.java:323) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:321) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:202) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1108) ~[spring-context-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:868) ~[spring-context-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:550) ~[spring-context-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.boot.web.servlet.context.ServletWebServerApplicationContext.refresh(ServletWebServerApplicationContext.java:141) ~[spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:747) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at org.springframework.boot.SpringApplication.refreshContext(SpringApplication.java:397) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at org.springframework.boot.SpringApplication.run(SpringApplication.java:315) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1226) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1215) [spring-boot-2.2.2.RELEASE.jar:2.2.2.RELEASE]
at com.tz.mooc.Application.main(Application.java:10) [classes/:na]
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[na:1.8.0_144]
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[na:1.8.0_144]
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[na:1.8.0_144]
at java.lang.reflect.Method.invoke(Method.java:498) ~[na:1.8.0_144]
at org.springframework.boot.devtools.restart.RestartLauncher.run(RestartLauncher.java:49) [spring-boot-devtools-2.2.2.RELEASE.jar:2.2.2.RELEASE]
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(ars)]
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:403) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:378) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.afterPropertiesSet(LocalContainerEntityManagerFactoryBean.java:341) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1855) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1792) ~[spring-beans-5.2.2.RELEASE.jar:5.2.2.RELEASE]
... 21 common frames omitted
Caused by: org.hibernate.MappingException: Could not determine type for: java.util.List, at table: user, for columns: [org.hibernate.mapping.Column(ars)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:488) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:455) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.mapping.Property.isValid(Property.java:227) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:624) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.mapping.RootClass.validate(RootClass.java:267) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.boot.internal.MetadataImpl.validate(MetadataImpl.java:343) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.boot.internal.SessionFactoryBuilderImpl.build(SessionFactoryBuilderImpl.java:461) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:1237) ~[hibernate-core-5.4.9.Final.jar:5.4.9.Final]
at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:58) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:365) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:391) ~[spring-orm-5.2.2.RELEASE.jar:5.2.2.RELEASE]
... 25 common frames omitted
Thank you very much for your help
答案1
得分: 0
最后,我只是自己在数据库中创建了一张表,并将用户-课程表视为普通表,以避免使用"@ManyToMany"。我认为这不是最佳方法,看起来很混乱。也许有人会给我更好的答案。我认为最好创建一个演示来测试。
英文:
finally I just create a table in db by myself, and treat the user-course table like normal to avoid "@ManyToMany". I think it is not a best way, and it looks confused. Maybe someone will give me the better answer. I think it is better to create a demo to test.
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