英文:
Get node value between curly braces with Java Pattern.compile()
问题
以下是翻译好的内容：
我想从以下字符串中提取id的值
.... code=1234random22211, request={ id='randomValue like: aa1a-bb2b-cc3c-ddd4d', event='new' version='1'} ...
我已经制定了以下模式：
Pattern p = Pattern.compile("/^.*code=" + currentCode + ", request=\\{([^}]*)");
Matcher m = eventIdPatterns.matcher(logs);
boolean idExists = m.matches();
该模式成功评估了代码：https://regex101.com/r/1kJ5Uo/2 但是我不知道如何在模式中去掉剩余的\。
评估结果总是为false，因为模式p被视为：/^.*orderCode=20200409174150852, request=\{([^}]*)。
有人可以告诉我如何在执行m.matches()时摆脱模式中的额外\，或者提供另一个提取id值或花括号内内容的模式吗？
英文:
I want to extract the value of id from the following string
.... code=1234random22211, request={ id='randomValue like: aa1a-bb2b-cc3c-ddd4d', event='new' version='1'} ...
I have the made the following pattern:
Pattern p = Pattern.compile("/^.*code=" + currentCode + ", request=\\{([^}]*)");
Matcher m = eventIdPatterns.matcher(logs);
boolean idExists = m.matches();
The pattern evaluates the code successfully: https://regex101.com/r/1kJ5Uo/2 but I don't know how to get rid of the remaining \ in the pattern.
The evaluation is always false because pattern p is seens as: /^.*orderCode=20200409174150852, request=\{([^}]*).
Can somebody indicate me how to get rid of that extra \ from pattern when I perform m.matches() or another pattern to extract the value of id or the content between curly braces
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