Spring MVC – 无法打开 ServletContext 资源 /WEB-INF/dispatcher-servlet.xml

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英文:

Spring mvc - Could not open ServletContext resource /WEB-INF/dispatcher-servlet.xml

问题

我在使用Spring MVC Web应用程序时遇到了问题，我无法弄清楚我做错了什么，我目前正在按照教程进行，我完全按照它的步骤进行操作，但我无法理解为什么即使文件存在，仍然会抛出FileNotFoundException。

这是我的dispatcher-servlet.xml内容：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
       http://www.springframework.org/schema/beans/spring-beans.xsd">

    <context:component-scan base-package="com.springWeb" />

    <!-- 提供转换、格式化和验证的支持 -->
</beans>

以下是我的web.xml内容：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
         version="4.0">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/web/WEB-INF/dispatcher-servlet.xml</param-value>
    </context-param>
    
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

详细日志信息如下：

类型 异常报告

消息 Servlet.init() for servlet [dispatcher] threw exception

描述 服务器遇到内部错误，阻止它满足请求。

异常

javax.servlet.ServletException: Servlet.init() for servlet [dispatcher] threw exception
    ...
根本原因

org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/dispatcher-servlet.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]
    ...
原因

java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]
    ...

能否有人指导我？

英文:

I'm facing a problem with spring mvc web application, i can't figure out what i did wrong, I am currently following a tutorial and I do exactly what it does, i can't understand why the FileNotFoundException is thrown even if the file exist.

Here is my dispatcher-servlet.xml

  &lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
   &lt;beans xmlns=&quot;http://www.springframework.org/schema/beans&quot;
   xmlns:xsi=&quot;http://www.w3.org/2001/XMLSchema-instance&quot;
   xmlns:context=&quot;http://www.springframework.org/schema/context&quot;
   xmlns:mvc=&quot;http://www.springframework.org/schema/mvc&quot;
   xsi:schemaLocation=&quot;http://www.springframework.org/schema/beans 
   http://www.springframework.org/schema/beans/spring-beans.xsd">

   &lt;context:component-scan base-package=&quot;com.springWeb&quot; /&gt;

   &lt;!--Provide support for conversion, formatting and validation --&gt;
   &lt;/beans&gt;

and the following is my web.xml

   &lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
   &lt;web-app xmlns=&quot;http://xmlns.jcp.org/xml/ns/javaee&quot;
     xmlns:xsi=&quot;http://www.w3.org/2001/XMLSchema-instance&quot;
     xsi:schemaLocation=&quot;http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd&quot;
     version=&quot;4.0&quot;&gt;
&lt;context-param&gt;
    &lt;param-name&gt;contextConfigLocation&lt;/param-name&gt;
    &lt;param-value&gt;/web/WEB-INF/dispatcher-servlet.xml&lt;/param-value&gt;
&lt;/context-param&gt;

&lt;servlet&gt;
    &lt;servlet-name&gt;dispatcher&lt;/servlet-name&gt;
    &lt;servlet-class&gt;org.springframework.web.servlet.DispatcherServlet&lt;/servlet-class&gt;
    &lt;load-on-startup&gt;1&lt;/load-on-startup&gt;
&lt;/servlet&gt;
&lt;servlet-mapping&gt;
    &lt;servlet-name&gt;dispatcher&lt;/servlet-name&gt;
    &lt;url-pattern&gt;/&lt;/url-pattern&gt;
&lt;/servlet-mapping&gt;

</web-app>

The exhaustive logs

Type Rapport d&#39;exception

 message Servlet.init() for servlet [dispatcher] threw exception

 description Le serveur a rencontr&#233; une erreur interne qui l&#39;a emp&#234;ch&#233; de satisfaire la requ&#234;te.

 exception

javax.servlet.ServletException: Servlet.init() for servlet [dispatcher] threw exception
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:543)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:81)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:688)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:609)
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:818)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1623)
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:748)

root cause 

org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document     from ServletContext resource [/WEB-INF/dispatcher-servlet.xml]; nested exception is java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]
org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:344)
org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:304)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:188)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:224)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:195)
org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:125)
org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:94)
org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:133)
org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:622)
org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:518)
org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:696)
org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:662)
org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:710)
org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:587)
org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:526)
org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:169)
javax.servlet.GenericServlet.init(GenericServlet.java:158)
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:543)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:81)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:688)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:609)
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:818)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1623)
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:748)

cause m&#232;re

java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]
org.springframework.web.context.support.ServletContextResource.getInputStream(ServletContextResource.java:158)
org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:330)
org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:304)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:188)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:224)
org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:195)
org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:125)
org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:94)
org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:133)
org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:622)
org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:518)
org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:696)
org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:662)
org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:710)
org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:587)
org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:526)
org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:169)
javax.servlet.GenericServlet.init(GenericServlet.java:158)
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:543)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:81)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:688)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:609)
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:818)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1623)
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:748)

can someone guide me

答案1

得分: 0

使用以下方式在您的调度程序servlet内部使用init-param标签：

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
    </init-param>
</servlet>

您在context-param内部所做的操作不会被Spring视为配置文件，而只会被视为一般的参数存在于servlet上下下文中，作为一个可由所有servlet访问的字符串。

英文:

Use init-param tag inside your dispatcher servlet like this :

&lt;servlet&gt;
	&lt;servlet-name&gt;dispatcher&lt;/servlet-name&gt;
	&lt;servlet-class&gt;org.springframework.web.servlet.DispatcherServlet&lt;/servlet-class&gt;
	&lt;init-param&gt;
		&lt;param-name&gt;contextConfigLocation&lt;/param-name&gt;
		&lt;param-value&gt;/WEB-INF/dispatcher-servlet.xml&lt;/param-value&gt;
	&lt;/init-param&gt;
&lt;/servlet&gt;

In what you did inside context-param, will not be taken by Spring as a configuration file but just as a general parameter inside the servlet context, accessible to all servlets as a String .

huangapple
  • 本文由 发表于 2020年4月9日 23:27:08
  • 转载请务必保留本文链接：https://java.coder-hub.com/61124648.html
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