英文:
Need to make a Counter using enum ordinals
问题
以下是您提供的代码的翻译部分：
我需要为剪刀石头布游戏制作一个计数器数组，但是不知道如何使用户输入调用枚举，我需要使游戏的动作成为一个计数器，以便进行使用和比较。
这是我的枚举
public enum Moves {
Rock(1),
Paper(2),
Scissors(3),
Lizard(4),
Spock(5), ;
private int countOf = 0;
private int moveVal;
private ArrayList<Moves> movesList = new ArrayList<>();
Moves(int moveVal) {
}
public int getmoveVal() {
return moveVal;
}
public int getCountOf() {
for(Moves moveList : Moves.values()) {
countOf++;
}
return countOf;
}
这是会调用它的我的类
public static void main(String[] args) {
RockPaperScissorGame rsg = new RockPaperScissorGame(3);
Moves move[] = Moves.values();
int playerMove = 0;
for(int i = 0; i < move.length; i++) {
}
boolean continueGame = true;
@SuppressWarnings("resource")
Scanner keyboard = new Scanner(System.in);
while(continueGame)
{
System.out.println(rsg.moveChoices());
System.out.println("Enter Move:(1,2,3,4 or 5):");
playerMove = keyboard.nextInt();
rsg.playRound(move);
System.out.printf("AI %s!%n", rsg.getAIOutcome().toString());
System.out.printf("Player %s!%n", rsg.getPlayerOutcome().toString());
System.out.println(rsg.moveOutcome());
System.out.println(rsg.currentScore());
if(rsg.isGameOver())
{
System.out.println(rsg.currentWinTotal());
System.out.println("Do you want to Play Again(1 - Yes , 2 - No):");
int answer = keyboard.nextInt();
if(answer == 2)
{
continueGame = false;
}
else
{
rsg.reset();
}
}
}
请注意，这只是代码的翻译部分，我没有回答关于如何解决您提出的问题的具体问题。如果您需要有关代码的具体问题的帮助，请提出具体的问题，我将尽力提供帮助。
英文:
I need to make a counter array for a Rock Paper Scissors game but can not figure out how to make user input call the enum, and i need to make the moves for the game a counter for them to be used and compared to.
This is my enum
public enum Moves {
Rock(1),
Paper(2),
Scissors(3),
Lizard(4),
Spock(5), ;
private int countOf = 0;
private int moveVal;
private ArrayList<Moves> movesList = new ArrayList<>();
Moves(int moveVal) {
}
public int getmoveVal() {
return moveVal;
}
public int getCountOf() {
for(Moves moveList : Moves.values()) {
countOf++;
}
return countOf;
}
And this is my class that would call it
public static void main(String[] args) {
RockPaperScissorGame rsg = new RockPaperScissorGame(3);
Moves move[] = Moves.values();
int playerMove = 0;
for(int i = 0; i < move.length; i++) {
}
boolean continueGame = true;
@SuppressWarnings("resource")
Scanner keyboard = new Scanner(System.in);
while(continueGame)
{
System.out.println(rsg.moveChoices());
System.out.println("Enter Move:(1,2,3,4 or 5):");
playerMove = keyboard.nextInt();
rsg.playRound(move);
System.out.printf("AI %s!%n", rsg.getAIOutcome().toString());
System.out.printf("Player %s!%n", rsg.getPlayerOutcome().toString());
System.out.println(rsg.moveOutcome());
System.out.println(rsg.currentScore());
if(rsg.isGameOver())
{
System.out.println(rsg.currentWinTotal());
System.out.println("Do you want to Play Again(1 - Yes , 2 - No):");
int answer = keyboard.nextInt();
if(answer == 2)
{
continueGame = false;
}
else
{
rsg.reset();
}
}
}
答案1
得分: 0
你可以通过迭代values来找到与moveVal匹配的Move：
public Move fromMoveVal(int moveVal) {
for (Move m : Move.values()) if (m.moveVal == moveVal) return m;
return null;
}
英文:
You can iterate through values to find a Move matching that moveVal:
public Move fromMoveVal(int moveVal) {
for (Move m : Move.values()) if (m.moveVal == moveVal) return m;
return null;
}
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