英文:
Java Array: Finding how many numbers are less then the Mean
问题
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many integers should we analyze?");
int num;
num = in.nextInt();
while (num <= 2) {
System.out.println("Please reenter, integer must be greater than 1");
num = in.nextInt();
}
int[] arr = new int[num];
System.out.println("Please enter the " + num + " integers:");
for (int i = 0; i < arr.length; i++) {
arr[i] = in.nextInt();
}
System.out.print("Number of integers input: " + num);
System.out.println();
double total = 0;
for (int element : arr) {
total += element;
}
System.out.print("Total: " + (int) total);
System.out.println();
double mean = 0;
if (arr.length > 0) {
mean = total / arr.length;
}
System.out.print("Mean: " + mean);
int big = arr[0];
for (int i = 0; i < arr.length; i++) {
if (arr[i] > big) {
big = arr[i];
}
}
System.out.println();
System.out.print("Largest: " + big);
System.out.println();
///////////////////////////////////////////////////////////////////////////////////////////////
int less;
for (int i = 0; i < mean; i++) {
int num2 = i;
int[] arr2 = new int[num2];
int count = 0;
while (num2 != 0) {
num2 /= 10;
++count;
System.out.print("Numbers less than the mean: " + count);
}
}
//////////////////////////////////////////////////////////////////////////////////////////////
}
请注意，上述代码可能有一些逻辑错误，特别是在计算小于平均值的数字的部分。如果您需要更详细的帮助或修复，请随时提问。
英文:
- Okay so im trying to find the amount of numbers that are less then
the mean of the first array. Everything but the last part is working and i
cant figure it out. The code at the bottom is what im having problems with.
for example. if i enter 1 2 3 4 5. the mean is 3 and, 1 and 2 are less then 3. so the answer would be 2 numbers.
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
System.out.println("How many integers should we analyze?" );
int num;
num=in.nextInt();
while ( num <= 2)
{
System.out.println( "Please reenter, integer must be greater than 1" );
num=in.nextInt();
}
int[] arr = new int[num];
System.out.println( "Please enter the "+ num +" integers:" );
for (int i = 0; i < arr.length; i++)
{
arr[i] = in.nextInt();
}
System.out.print("Number of integers input: " + num);
System.out.println();
double total = 0;
for( int element : arr) {
total += element;
}
System.out.print("Total: " + (int) total);
System.out.println();
double mean = 0;
if ( arr.length > 0) {
mean = total / arr.length;
}
System.out.print("Mean: " + mean );
int big = arr[0];
for (int i = 0 ; i < arr.length; i++) {
if (arr[i] > big) {
big = arr[i];
}
}
System.out.println();
System.out.print("Largest: " + big);
System.out.println();
///////////////////////////////////////////////////////////////////////////////////////////////
int less;
for(int i=0;i<mean;i++) {
int num2 = i;
int[] arr2 = new int[num2];
int count = 0;
while ( num2 != 0 )
{
num2/=10;
++count;
System.out.print("Numbers less than the mean: " + count);
}
}
//////////////////////////////////////////////////////////////////////////////////////////////
}
}
答案1
得分: 0
你可以使用下面的代码：
int count = 0;
for (int i = 0; i < arr.length; i++) {
if (arr[i] < mean)
count++;
}
System.out.println("小于平均值的数字个数为：" + count);
这段代码的作用是遍历所有原始整数，如果某个整数小于平均值，就将计数变量增加1。
英文:
you could use this code below
int count = 0;
for(int i =0;i< arr.length;i++) {
if(arr[i] < mean)
count++;
}
System.out.println("numbers less than mean " + count);
what this does is it loops through all of the original integers and if one is less than the mean, the count variable goes up by 1.
答案2
得分: 0
你应该遍历数组并检查每个元素是否小于均值。如果是的话，就增加一个整数。
int less = 0;
for (int i = 0; i < arr.length; i++) {
if (arr[i] < mean) {
less++;
}
}
System.out.print("小于均值的数字：" + less);
英文:
You should iterate over the array and check each element if they are under the mean. If yes, then increment an integer.
int less = 0;
for(int i = 0; i < arr.length; i++) {
if(arr[i] < mean) {
less++;
}
}
System.out.print("Numbers less than the mean: " + less);
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