Java数组：查找比平均值小的数字数量

huangapple
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英文:

Java Array: Finding how many numbers are less then the Mean

问题

  1. public static void main(String[] args) {
  2.     Scanner in = new Scanner(System.in);
  3.     System.out.println("How many integers should we analyze?");
  4.     int num;
  5.     num = in.nextInt();
  6.     while (num <= 2) {
  7.         System.out.println("Please reenter, integer must be greater than 1");
  8.         num = in.nextInt();
  9.     }
  10.     
  11.     int[] arr = new int[num];
  12.     System.out.println("Please enter the " + num + " integers:");
  13.     for (int i = 0; i < arr.length; i++) {
  14.         arr[i] = in.nextInt();
  15.     }
  16.     
  17.     System.out.print("Number of integers input: " + num);
  18.     System.out.println();
  19.     
  20.     double total = 0;
  21.     for (int element : arr) {
  22.         total += element;
  23.     }
  24.     System.out.print("Total: " + (int) total);
  25.     System.out.println();
  26.     
  27.     double mean = 0;
  28.     if (arr.length > 0) {
  29.         mean = total / arr.length;
  30.     }
  31.     System.out.print("Mean: " + mean);
  32.     
  33.     int big = arr[0];
  34.     for (int i = 0; i < arr.length; i++) {
  35.         if (arr[i] > big) {
  36.             big = arr[i];
  37.         }
  38.     }
  39.     System.out.println();
  40.     
  41.     System.out.print("Largest: " + big);
  42.     System.out.println();
  43.     
  44.     ///////////////////////////////////////////////////////////////////////////////////////////////
  45.     
  46.     int less;
  47.     for (int i = 0; i < mean; i++) {
  48.         int num2 = i;
  49.         int[] arr2 = new int[num2];
  50.         int count = 0;
  51.         while (num2 != 0) {
  52.             num2 /= 10;
  53.             ++count;
  54.             System.out.print("Numbers less than the mean: " + count);
  55.         }
  56.     }
  57.     //////////////////////////////////////////////////////////////////////////////////////////////
  58. }

请注意，上述代码可能有一些逻辑错误，特别是在计算小于平均值的数字的部分。如果您需要更详细的帮助或修复，请随时提问。

英文:
  • Okay so im trying to find the amount of numbers that are less then
    the mean of the first array. Everything but the last part is working and i
    cant figure it out. The code at the bottom is what im having problems with.

for example. if i enter 1 2 3 4 5. the mean is 3 and, 1 and 2 are less then 3. so the answer would be 2 numbers.

  1. public static void main(String[] args) {
  2. 		
  3. 		Scanner in=new Scanner(System.in);	
  4. 			System.out.println(&quot;How many integers should we analyze?&quot; );
  5. 				int num; 
  6. 					num=in.nextInt();				
  7. while ( num &lt;= 2) 
  8. {		
  9. System.out.println( &quot;Please reenter, integer must be greater than 1&quot; );
  10. num=in.nextInt();
  11. }	
  12. 	 int[] arr = new int[num];
  13. 		System.out.println( &quot;Please enter the &quot;+ num +&quot; integers:&quot; );	
  14. 			for (int i = 0; i &lt; arr.length; i++) 
  15. 	{
  16. 		arr[i] = in.nextInt(); 
  17. 	}	    			
  18. 	System.out.print(&quot;Number of integers input: &quot; + num);
  19. 	System.out.println();
  20. 	
  21. 	double total = 0;
  22. 	for( int element : arr) {
  23. 		total += element;
  24. 	 
  25. 	}
  26. 	System.out.print(&quot;Total: &quot; + (int) total);
  27. 	System.out.println();
  28. 	 
  29. 	
  30. 	double mean = 0;
  31. 	 if ( arr.length &gt; 0) {
  32. 		 mean = total / arr.length;	 
  33. 	 }
  34. 	 System.out.print(&quot;Mean: &quot; + mean );
  35. 	
  36. 	 
  37. 	 int big = arr[0];
  38. 	for (int i = 0 ; i &lt; arr.length; i++) {
  39. 		if (arr[i] &gt; big) {
  40. 			big = arr[i];  			
  41. 		}
  42. 	}
  43. 	System.out.println();
  44. 	
  45. 	
  46. 	System.out.print(&quot;Largest: &quot; + big);	
  47. 	System.out.println();
  49. ///////////////////////////////////////////////////////////////////////////////////////////////    	
  50. 	
  51.     int less;               
  52. 	for(int i=0;i&lt;mean;i++) {
  53. 		
  54. 		int num2 = i;
  55. 	int[] arr2 = new int[num2];
  56. 		int count = 0;
  57. 	while ( num2 != 0 )
  58. 	{
  59. 		num2/=10;
  60. 		++count;
  61. 		System.out.print(&quot;Numbers less than the mean: &quot; + count);
  62. 	}	
  63. 	}
  64. //////////////////////////////////////////////////////////////////////////////////////////////
  66. }
  68. }

答案1

得分: 0

你可以使用下面的代码：

  1. int count = 0;
  2. for (int i = 0; i < arr.length; i++) {
  3.     if (arr[i] < mean)
  4.         count++;
  5. }
  6. System.out.println("小于平均值的数字个数为：" + count);

这段代码的作用是遍历所有原始整数，如果某个整数小于平均值，就将计数变量增加1。

英文:

you could use this code below

  1. int count = 0;
  2. for(int i =0;i&lt; arr.length;i++) {
  3. 	if(arr[i] &lt; mean)
  4. 		count++;
  5. }
  6. System.out.println(&quot;numbers less than mean &quot; + count);

what this does is it loops through all of the original integers and if one is less than the mean, the count variable goes up by 1.

答案2

得分: 0

你应该遍历数组并检查每个元素是否小于均值。如果是的话，就增加一个整数。

  1. int less = 0;
  2. for (int i = 0; i < arr.length; i++) {
  3.     if (arr[i] < mean) {
  4.         less++;
  5.     }
  6. }
  7. System.out.print("小于均值的数字：" + less);
英文:

You should iterate over the array and check each element if they are under the mean. If yes, then increment an integer.

  1. int less = 0;
  2. for(int i = 0; i &lt; arr.length; i++) {
  3.     if(arr[i] &lt; mean) {
  4.         less++;
  5.     }
  6. }
  7. System.out.print(&quot;Numbers less than the mean: &quot; + less);

huangapple
  • 本文由 发表于 2020年5月5日 06:57:44
  • 转载请务必保留本文链接：https://java.coder-hub.com/61603012.html
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