英文:
The condition is not checking. Java, AWT
问题
我正在使用Java的AWT编写一个小型登录表单。在检查登录的用户输入时遇到了一个问题：当用户将“admin”输入为登录名并将“password”输入为密码时，程序会输出“成功！”，但无论如何我都会收到“错误！”消息，即使输入的数据满足条件。
因此，我应该如何调整程序以正确检查条件？
代码：
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Login extends JFrame {
private JButton button = new JButton("确认");
private JLabel label1 = new JLabel("登录：");
private JTextField login = new JTextField("", 8);
private JLabel label2 = new JLabel("密码：");
private JTextField pswrd = new JTextField("", 8);
public Login() {
super("请登录");
this.setBounds(100, 100, 250, 100);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
Container container = this.getContentPane();
container.setLayout(new GridLayout(3, 2, 2, 2));
container.add(label1);
container.add(label2);
container.add(login);
container.add(pswrd);
button.addActionListener(new ButtonEvent());
container.add(button);
}
class ButtonEvent implements ActionListener {
public void actionPerformed(ActionEvent e) {
if (login.getText().equals("admin") && pswrd.getText().equals("password")) {
JOptionPane.showMessageDialog(null, "成功！", "输出", JOptionPane.PLAIN_MESSAGE);
} else {
JOptionPane.showMessageDialog(null, "错误！", "输出", JOptionPane.PLAIN_MESSAGE);
}
}
}
public static void main(String[] args) {
Login app = new Login();
app.setVisible(true);
}
}
请注意，我只提供了代码的翻译部分，没有包含额外的内容。
英文:
I am writing a small login form at Java using AWT. Faced a problem while checking user input for login: I need, when user inputed "admin" as login and "password" as password, program outputting "Succes!", but anyway I get "Wrong!" message, even if inputed data meet the condition.
So, what should I do so that the program checks the condition correctly?
Code:
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Login extends JFrame {
private JButton button = new JButton("Confirm");
private JLabel label1 = new JLabel("Login:");
private JTextField login = new JTextField("", 8);
private JLabel label2 = new JLabel("Password:");
private JTextField pswrd = new JTextField("", 8);
public Login() {
super("Please log in");
this.setBounds(100, 100, 250, 100);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
Container container = this.getContentPane();
container.setLayout(new GridLayout(3,2,2,2));
container.add(label1);
container.add(label2);
container.add(login);
container.add(pswrd);
button.addActionListener(new ButtonEvent());
container.add(button);
}
class ButtonEvent implements ActionListener {
public void actionPerformed(ActionEvent e) {
if (login.getText() == "admin" && pswrd.getText() == "password")
{
JOptionPane.showMessageDialog(null, "Succes!", "Output", JOptionPane.PLAIN_MESSAGE);
}
else
{
JOptionPane.showMessageDialog(null, "Wrong!", "Output", JOptionPane.PLAIN_MESSAGE);
}
}
}
public static void main(String[] args) {
Login app = new Login();
app.setVisible(true);
}
}
答案1
得分: 2
只需尝试使用.equals()，而不是使用==。
英文:
Just try .equals() instead of ==
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