英文:
How do overloading methods decide on types in Java
问题
为什么这将 100 视为整型？而不是字节或短整型？
System.out.print(100);
我在某处读到这样的解释：
> 编译器会选择按照隐式转换的顺序，使用与参数类型最接近的方法。
我不明白这里所说的「最接近」是什么意思。这与内存占用或者其他什么有关吗？
英文:
Why does this treat 100 as an int? Why not as a byte or short?
System.out.print(100);
I read this somewhere:
> The compiler chooses the method that has the closest type of the argument in order of the implicit casting.
I don't understand what it means by "closest". Is it to do with the memory it takes in RAM or something?
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