英文:
How to find indexes of array with value = 0? Java
问题
以下是翻译好的内容：
有没有办法找到数组中 0 的索引？
我是新手，所以我不太了解。
Scanner scanner = new Scanner(System.in);
System.out.println("输入数组大小 - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
}
int numberOfZeros = 0;
for (int i = 0; i < arraySize; i++) {
if (array[i] == 0) {
numberOfZeros++;
}
}
if (numberOfZeros == 0) {
System.out.print("数组中没有零！");
} else if (numberOfZeros > 0) {
System.out.print("数组中零的个数 - " + numberOfZeros);
}
英文:
Is there any way to find indexes of 0's in my array?
Im a newbie, so i dont know much.
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Array Size - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
}
int numberOfZeros = 0;
for (int i = 0; i < arraySize; i++) {
if (array[i] == 0) {
numberOfZeros++;
}
}
if (numberOfZeros == 0) {
System.out.print("No Zero's in Array!");
} else if (numberOfZeros > 0) {
System.out.print("Number of Zero's in Array - " + numberOfZeros);
}
答案1
得分: 0
只打印（或者按照你需要的方式处理）索引 i。你已经找到了零：
for (int i = 0; i < arraySize; i++) {
if (array[i] == 0) {
numberOfZeros++;
System.out.print("零的值位于索引：" + i);
}
}
英文:
Just print (or do whatever you need to do with it) index i. You already found zeros:
for (int i = 0; i < arraySize; i++) {
if (array[i] == 0) {
numberOfZeros++;
System.out.print("The value zero is at index: " + i);
}
}
答案2
得分: 0
你可以解析数组，并每次遇到零时记录索引：
Scanner scanner = new Scanner(System.in);
System.out.println("输入数组大小 - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
}
for (int i = 0; i < arraySize; i++) {
if (array[i] == 0) {
System.out.println("索引 " + i + " 处有零");
}
}
英文:
You can parse the array , and each time you encounter a zero you can stock the index :
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Array Size - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
}
for(int i=0;i<arraySize;i++) {
if ( array[i] == 0 ) {
System.out.println(" There is a zero on the index "+i );
}
}
答案3
得分: 0
你可以使用 ArrayList 来跟踪索引，在找到零元素时将其打印出来。
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("请输入数组大小 - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
int numberOfZeros = 0;
List<Integer> indexes = new ArrayList<>();
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
if (array[i] == 0) {
numberOfZeros++;
indexes.add(i);
}
}
if (numberOfZeros == 0) {
System.out.print("数组中没有零元素！");
} else if (numberOfZeros > 0) {
System.out.print("数组中零元素的数量 - " + numberOfZeros + "，位置在： " + indexes);
}
scanner.close();
}
英文:
You can keep track the indexes using ArrayList and print it when you find zeros
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.println("Enter Array Size - ");
int arraySize = scanner.nextInt();
int[] array = new int[arraySize];
int a = -1;
int numberOfZeros = 0;
List<Integer> indexes = new ArrayList<>();
for (int i = 0; i < arraySize; i++) {
array[i] = a + (int) (Math.random() * 10);
if (array[i] == 0) {
numberOfZeros++;
indexes.add(i);
}
}
if (numberOfZeros == 0) {
System.out.print("No Zero's in Array!");
} else if (numberOfZeros > 0) {
System.out.print("Number of Zero's in Array - " + numberOfZeros + " , in positions: " + indexes);
}
scanner.close();
}
答案4
得分: 0
只要您已经在循环遍历数组并对其进行计数，只需将它们添加到 List<Integer> 以供将来参考。
然而，如果您需要在与其他代码隔离的情况下找到它们，可以按照以下方式进行。
int[] vals = { 1,2, 0,20,33,2, 0, 99,9,10,0,4};
int[] zeroIndices = IntStream.range(0,vals.length)
.filter(i->vals[i] == 0)
.toArray();
System.out.println(zeroIndices.length + " 个零被找到！");
System.out.println(Arrays.toString(zeroIndices));
输出结果为
找到 3 个零！
[2, 6, 10]
英文:
As long as you are already looping thru the array and counting them, just add them to a List<Integer> for future reference.
However, if you need to find them in isolation of other code you can do it this way.
int[] vals = { 1,2, 0,20,33,2, 0, 99,9,10,0,4};
int[] zeroIndices = IntStream.range(0,vals.length)
.filter(i->vals[i] == 0)
.toArray();
System.out.println(zeroIndices.length + " zeroes found!");
System.out.println(Arrays.toString(zeroIndices));
Prints
3 zeroes found!
[2, 6, 10]
</details>
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