Is there a way to make thrown exceptions run first before anything else is executed?

Here is the output of my code

	[Opening file and detecting number of duplicate serial numbers...]

--------- [Program terminated] Files having been saved and closed. -----------

		== Thank you for using Cargoship Info Correction == - File could not be found: 
noduplicate (No such file or directory)

As you can see, the very last part, "file could not be found: etc.." is oddly placed. It should be between Opening file and Program terminated, and in my code it is placed as such. However, when I run my code, it seems because exception handling are slower, so everytime I run my code, they may appear in different places instead of the right place.

Is there any way around this?

For the actual code if needed, here is the part:

System.out.println("\n\t[Opening file and detecting number of duplicate serial numbers...]\n");
		try {
			//counting number of objects in file
			int count = cargosCount(initialCargo);
			
			if(count <= 1) {
				System.out.println("\t[Terminating program - File \"" + initialCargo + "\" has no duplicated serial number, all is well!]\n");
			}
			else {
etc...

Then in the finally-clause of the try-block, I have the "terminated" message printed out.

**EDIT: Thanks for commenting, I found a way to fix it, had to print the error message in the same print as my own message:
System.err.println("- File could not be found: " + e.getMessage() + "\n");

**Re-EDIT: actually, problem still occurs in another way:

		catch (InputMismatchException e) {
			System.err.println("Please enter a valid input.");
		}
		catch (IOException e) {
			System.out.println("[IOException error] Stack Trace:");
			e.printStackTrace();
		}
		finally {
			System.out.print("--------- [Program terminated] Files having been saved and closed. -----------"
					+ "\n\n\t== Thank you for using Cargoship Info Correction ==");
			read.close();
		}

In this code, my InputMismatchException is printed after the finally-clause...

This is happening because e.printStackTrace() prints to the standard error stream (System.err), while your other messages are printed to the standard output stream (System.out). This is done by default to make it easier to route error messages to a different log file (for example) than regular output.

If you need regular messages and error messages to appear in sequence, you need to send them to the same output stream. You can do that by calling System.err.println for regular messages (NOT recommended) or by passing the standard output stream reference to the printStackTrace method.

e.printStackTrace(System.out);

Run the simplified example below, and note that the ArithmeticException error message is reliably printed after Message 2.

public class Printer {
	public static void main(String[] args) {
		System.out.println("Message 1...");
		
		try {
			System.out.println("Message 2...");
			int x = 10 / 0;
		}
		catch (Exception e) {
			e.printStackTrace(System.out);
			System.out.println("Message 3...");
		}
		finally {
			System.out.println("Message 4...");
		}
	}
}