英文:
How to get StackPane's child using the child's variable name
问题
TabPane tabpaneSubs = new TabPane();
stackPane.getChildren().add(tabpaneSubs);
button.setOnAction(actionEvent -> {
tabpaneSubs.toFront();
}
英文:
TabPane tabpaneSubs = new TabPane();
stackPane.getChildren().add(tabpaneSubs);
button.setOnAction( actionEvent -> {
stackPane.getChildren().get(1).toFront();
}
Instead of using .get(1) i want to use the variable's name : tabpaneSubs
How do i do that ?
答案1
得分: 1
这应该可以正常工作，因为你在编译时已经知道你的 TabPane 是一个子节点：
button.setOnAction(actionEvent -> {
tabpaneSubs.toFront();
});
更一般地，你应该使用 id 属性来找到特定的元素：
tabpaneSubs.setId("my-tab-pane");
button.setOnAction(actionEvent -> {
for(Node node : stackPane.getChildren()) {
if("my-tab-name".equals(node.getId())){
node.toFront();
return;
}
}
});
英文:
This should work simply because you already know your TabPane is a child at compile time:
button.setOnAction( actionEvent -> {
tabpaneSubs.toFront();
});
More generally, you should use the id property to find specific things
tabpaneSubs.setId("my-tab-pane");
button.setOnAction( actionEvent -> {
for(Node node : stackPane.getChildren()) {
if("my-tab-name".equals(node.getId()){
node.toFront();
return;
}
}
});
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